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  1. How do you simplify #sqrt (100/3)#? - Socratic

    (10sqrt3)/3 >"using the "color(blue)"law of radicals" •color(white)(x)sqrt(a/b)hArrsqrta/sqrtb •color(white)(x)sqrtaxxsqrta=a rArrsqrt(100/3)=sqrt100/sqrt3=10 ...

  2. How do you simplify sqrt (5)*sqrt (7)*sqrt3? | Socratic

    sqrt105 when multiplying square roots, we can rewrite it as sqrt (5*7*3) which simplifies to sqrt105

  3. What is the simplest exact value of #\sqrt { 20}#? - Socratic

    +-2sqrt5 First, we want to see if we can factor out any perfect squares out of sqrt20. We can rewrite this as: sqrt20=sqrt4*sqrt5 (because of the property sqrt(ab)=sqrta*sqrtb There are no perfect squares in …

  4. How do you expand and simplify sqrt3 (6-sqrt12)? | Socratic

    6sqrt (3)+-6 distribute the sqrt (3) sqrt (3) (6) - sqrt (12)sqrt (3) 6sqrt (3) - sqrt (12*3) 6sqrt (3) - sqrt (36) 6sqrt (3) +- 6 Lessons here: sqrt (a)sqrt (b) = sqrt (a*b), (so long as a and b are not negative) Other …

  5. What is the volume of the solid generated by revolving the region ...

    What is the volume of the solid generated by revolving the region bounded by #y=sqrt (sin6x), y=0#, and the #x#-axis, if #0<=x<=pi/6#?

  6. How do you write 10/17, .75, -1/8, sqrt (1/4), and 0 in order from ...

    After 0, you will have sqrt (1/4) since it is 0.5 indeed. Before 0.75, you must write 10/17 because of the fact that it equals 0.588. 0.75 is your last number and the greatest in this set.

  7. Question #5d6c5 - Socratic

    Feb 13, 2017 · 3tan^4x-2tan^2x-1=0 =>3tan^4x-3tan^2x+tan^2x-1=0 =>3tan^2x (tan^2x-1)+ (tan^2x-1)=0 => (3tan^2x+1) (tan^2x-1)=0 So 3tan^2x+1=0 =>tanx=sqrt (-1/3)->"not possible ...

  8. Find the sqrt (95)? | Socratic

    Jun 27, 2017 · sqrt (95) ~~9.7467 sqrt (95) Let's expand 95: 95= 5 xx 19 So, both 5and 19 are prime, so we can't move anything out of the square root. We'll need to use a calculator sqrt (95) ~~9.7467

  9. What is the possible answer for #sqrt27/16# ? How to ... - Socratic

    Explanation: We can use this rule for radicals to simplify the expression:

  10. If #sqrt (n+sqrt (n+sqrt (n+sqrt (n+sqrt (...)))))=3#, so n=? - Socratic

    Feb 27, 2018 · 6 sqrt (n+sqrt (n+sqrt (n+sqrt (n+sqrt (...)))))=3 So sqrt (n+3)=3 So n = 6